In the image given below,the total number of | vedclass

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(A) Let $n$ be the total number of reflections.From the geometry of the path,the horizontal distance $x$ covered between two consecutive reflections i

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$\frac{l}{{d	an 	heta }}$

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(A) Let $n$ be the total number of reflections.From the geometry of the path,the horizontal distance $x$ covered between two consecutive reflections is given by $	an 	heta = \frac{x}{d}$,which implies $x = d 	an 	heta$.The total length of the system is $l$. The light ray covers this horizontal distance $l$ through $n$ reflections.Therefore,the total horizontal distance is $n 	imes x = l$.Substituting $x$,we get $n(d 	an 	heta) = l$.Thus,the total number of reflections is $n = \frac{l}{d 	an 	heta}$.

In the image given below,the total number of reflections of the light ray before it exits the system will be

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