In the manufacture of NH_3 by Haber's process | vedclass

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Question

(C) The reaction is $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + Q \ kcal$. Since the reaction is exothermic $(+Q \ kcal)$,according to Le Chatelie

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Low temperature and high pressure

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(C) The reaction is $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + Q \ kcal$. Since the reaction is exothermic $(+Q \ kcal)$,according to Le Chatelier's principle,a low temperature favors the forward reaction to increase the yield of $NH_3$. Since the number of moles of gaseous products $(2)$ is less than the number of moles of gaseous reactants $(1+3=4)$,high pressure favors the forward reaction to increase the yield of $NH_3$. Therefore,low temperature and high pressure are the ideal conditions for maximum yield.

In the manufacture of $NH_3$ by Haber's process,the condition which would give maximum yield is $N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + Q \ kcal$.

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