In the molecule I_2Cl_6,choose the CORRECT st | vedclass

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(A) The structure of $I_2Cl_6$ is a dimer of $ICl_3$,which exists as a planar molecule.Each $I$ atom is $sp^3d$ hybridized with two lone pairs,making

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The molecule is planar.

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(A) The structure of $I_2Cl_6$ is a dimer of $ICl_3$,which exists as a planar molecule.Each $I$ atom is $sp^3d$ hybridized with two lone pairs,making the geometry around each $I$ atom square planar (if we consider the bridging atoms).There are $2$ bridging $Cl$ atoms and $4$ terminal $Cl$ atoms.Regarding the angles: $	heta_1$ is the $Cl-I-Cl$ angle involving bridging atoms,$	heta_2$ is the $Cl-I-Cl$ angle for terminal atoms,and $	heta_3$ is the $Cl-I-Cl$ angle between a terminal and a bridging atom.The correct order of angles is $	heta_3 > 	heta_2 > 	heta_1$.There are $20$ lone pairs in total ($3$ on each terminal $Cl$,$2$ on each bridging $Cl$,and $2$ on each $I$ atom: $4 	imes 3 + 2 	imes 2 + 2 	imes 2 = 12 + 4 + 4 = 20$).Thus,statement $(A)$ is the only correct statement among the options provided.

List-$I$ (molecule/ion)	List-$II$ (Number of lone pairs of electrons on the central atom)
$(A)$ $XeF_2$	$(I)$ $2$
$(B)$ $XeO_3$	$(II)$ $0$
$(C)$ $XeF_4$	$(III)$ $3$
$(D)$ $PF_6^-$	$(IV)$ $1$

In the molecule $I_2Cl_6$,choose the $CORRECT$ statement$(s)$.

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