In the nitrogen family,the H-M-H bond angle i | vedclass

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(B) The hydrides $MH_3$ have a pyramidal shape with a lone pair of electrons on the central atom. The $H-M-H$ bond angle is less than the tetrahedral

Vedclass · Accepted Answer

Almost pure $p-$ orbitals are used for $M-H$ bonding

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(B) The hydrides $MH_3$ have a pyramidal shape with a lone pair of electrons on the central atom. The $H-M-H$ bond angle is less than the tetrahedral angle of $109^o 28'$ due to lone pair-bond pair repulsion. As the electronegativity of the central atom $M$ decreases from $N$ to $Sb$,the bond pair of electrons shifts further away from the central atom. Consequently,the bond angle decreases and approaches $90^o$. This indicates that the bonding involves almost pure $p-$ orbitals of the central atom,with very little $s-$ character involved in the hybridization.

In the nitrogen family,the $H-M-H$ bond angle in the hydrides $MH_3$ gradually becomes closer to $90^o$ on going from $N$ to $Sb$. This shows that gradually

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