In the preceding question,the amount of Na_2C | vedclass

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(C) Phenolphthalein indicates the partial neutralization of $Na_2CO_3$ to $NaHCO_3$.$Meq. 	ext{ of } Na_2CO_3 + Meq. 	ext{ of } NaOH = Meq. 	ext{ o

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$0.530$

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(C) Phenolphthalein indicates the partial neutralization of $Na_2CO_3$ to $NaHCO_3$.$Meq. 	ext{ of } Na_2CO_3 + Meq. 	ext{ of } NaOH = Meq. 	ext{ of } HCl$$\frac{W}{E} 	imes 1000 + \frac{W}{E} 	imes 1000 = N 	imes V$(Suppose $Na_2CO_3 = a \, g$,$NaOH = b \, g$)$\frac{a}{53} 	imes 1000 + \frac{b}{40} 	imes 1000 = 300 	imes 0.1$ ..... $(1)$From the given data,$a = Na_2CO_3 = 0.53 \, g$.

In the preceding question,the amount of $Na_2CO_3$ present in the solution is ............. $g$.

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