In the preparation of compounds of $Xe$,Bartlett had taken $O_2^+PtF_6^-$ as a base compound. This is because:
- ABoth $O_2$ and $Xe$ have same size
- BBoth $O_2$ and $Xe$ have same electron gain enthalpy
- CBoth $O_2$ and $Xe$ have almost same ionisation enthalpy
- DBoth $Xe$ and $O_2$ are gases
Explore More
Similar Questions
Which noble gas is used in cryogenic studies?
Easy
View SolutionIn the following reaction, find the values of $a, b, p, q, r$ and $s$:
$a XeF_4 + b H_2O \rightarrow p Xe + q XeO_3 + r HF + s O_2$
$a XeF_4 + b H_2O \rightarrow p Xe + q XeO_3 + r HF + s O_2$
What are the elements at the end of periods $1$ to $7$ called? Which are these elements?
Easy
View SolutionWhich statement about noble gases is not correct?
The correct order of solubility in water for $He, Ne, Ar, Kr, Xe$ is
MediumAIIMS 2002
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo