In the process $BCl_3 + PH_3 \to BCl_3:PH_3$,the Lewis acid is
- A$BCl_3$
- B$PH_3$
- CBoth
- DNone
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The Born-Haber cycle is used to determine:
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View SolutionMatch the following molecules in Column $I$ with the number of lone pairs on their central atom in Column $II$.
Column $I$ (Molecules) Column $II$ (Number of lone pairs on central atom) $A. \ NH_3$ $1. \ \text{Two}$ $B. \ H_2O$ $2. \ \text{Three}$ $C. \ XeF_2$ $3. \ \text{Zero}$ $D. \ CH_4$ $4. \ \text{Four}$ $5. \ \text{One}$
| Column $I$ (Molecules) | Column $II$ (Number of lone pairs on central atom) |
|---|---|
| $A. \ NH_3$ | $1. \ \text{Two}$ |
| $B. \ H_2O$ | $2. \ \text{Three}$ |
| $C. \ XeF_2$ | $3. \ \text{Zero}$ |
| $D. \ CH_4$ | $4. \ \text{Four}$ |
| $5. \ \text{One}$ |
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