In the reaction shown,the major product obtai | vedclass

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Question

(C) The reaction involves the dehydrohalogenation of $3$-bromo-$2$-methylpentane using a strong base,ethoxide ion $(C_2H_5O^-)$,in ethanol $(C_2H_5OH)

Vedclass · Accepted Answer

$2-$methylpent$-2-$ene

Vedclass · Answer

(C) The reaction involves the dehydrohalogenation of $3$-bromo-$2$-methylpentane using a strong base,ethoxide ion $(C_2H_5O^-)$,in ethanol $(C_2H_5OH)$ at elevated temperatures $(\Delta)$.This is an $E2$ elimination reaction.The base abstracts a proton from the $\beta$-carbon atoms adjacent to the carbon bearing the bromine atom.There are two types of $\beta$-hydrogens available:$1$. Protons on the $C_2$ position (leading to $2$-methylpent$-2-$ene).$2$. Protons on the $C_4$ position (leading to $3$-methylpent$-2-$ene).$3$. Protons on the methyl group attached to $C_2$ (leading to $2$-methylpent$-1-$ene).According to Zaitsev's rule,the most substituted alkene is the major product.$2$-methylpent$-2-$ene is a trisubstituted alkene,which is more stable than the disubstituted alkenes ($3$-methylpent$-2-$ene and $2$-methylpent$-1-$ene).Therefore,$2$-methylpent$-2-$ene is the major product.

In the reaction shown,the major product obtained is:

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