In the reaction:2x + B_2H_6 longrightarrow [B | vedclass

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(D) $B_2H_6$ reacts with $NH_3$,primary $(I^o)$,and secondary $(II^o)$ amines to form an ionic compound of the type $[BH_2(x)_2]^+ [BH_4]^-$.However,w

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$(CH_3)_3N$

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(D) $B_2H_6$ reacts with $NH_3$,primary $(I^o)$,and secondary $(II^o)$ amines to form an ionic compound of the type $[BH_2(x)_2]^+ [BH_4]^-$.However,with tertiary $(III^o)$ amines like $(CH_3)_3N$,$B_2H_6$ undergoes symmetric cleavage to form a simple adduct: $B_2H_6 + 2(CH_3)_3N \longrightarrow 2(CH_3)_3N \cdot BH_3$.

In the reaction:
$2x + B_2H_6 \longrightarrow [BH_2(x)_2]^+ [BH_4]^-$
the amine $x$ will not be:

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In the reaction:$2x + B_2H_6 \longrightarrow [BH_2(x)_2]^+ [BH_4]^-$the amine $x$ will not be: