(C) In the reaction $A + B \to \text{Products}$,the rate law is given by $Rate = k[A]^x[B]^y$. When $B$ is taken in excess,its concentration remains e

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(C) In the reaction $A + B \to \text{Products}$,the rate law is given by $Rate = k[A]^x[B]^y$. When $B$ is taken in excess,its concentration remains effectively constant throughout the reaction. Thus,the rate equation becomes $Rate = k'[A]^x$,where $k' = k[B]^y$. This type of reaction,where a higher-order reaction appears to be first-order due to the excess of one reactant,is known as a pseudo-unimolecular reaction.

Class 12 Chemistry Chemical Kinetics Rate law , Rate constant , Order of Reaction and Molecularity

Easy

In the reaction $A + B \to \text{Products}$,if $B$ is taken in excess,then it is an example of

A
Second order reaction
B
Zero order reaction
C
Pseudounimolecular reaction
D
First order reaction

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Class 12 Questions

Class 12

Chemistry Questions

Chapter

Chemical Kinetics

Subtopic

Rate law , Rate constant , Order of Reaction and Molecularity

For a reaction whose rate expression is: Rate $= k[A]^{1/2}[B]^{3/2}$,the order would be

Medium

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Explain the order of reaction for complex reactions by giving examples.

Difficult

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Inversion of cane sugar is an example of $-$

Medium

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Select the rate law that corresponds to the data shown for the following reaction $A + B \to C$

$Expt. \ No.$ $[A]$ $[B]$ $Initial \ Rate$

$1$ $0.012$ $0.035$ $0.10$

$2$ $0.024$ $0.070$ $0.80$

$3$ $0.024$ $0.035$ $0.10$

$4$ $0.012$ $0.070$ $0.80$

$Expt. \ No.$	$[A]$	$[B]$	$Initial \ Rate$
$1$	$0.012$	$0.035$	$0.10$
$2$	$0.024$	$0.070$	$0.80$
$3$	$0.024$	$0.035$	$0.10$
$4$	$0.012$	$0.070$	$0.80$

DifficultAIIMS 2015

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For the decomposition of a compound $AB$ at $600 \ K$,the following data were obtained:
$[AB] \ (mol \ dm^{-3})$ Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$
$0.20$ $2.75 \times 10^{-8}$
$0.40$ $11.0 \times 10^{-8}$
$0.60$ $24.75 \times 10^{-8}$

The order for the decomposition of $AB$ is:

DifficultKCET 2009

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$[AB] \ (mol \ dm^{-3})$	Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$
$0.20$	$2.75 \times 10^{-8}$
$0.40$	$11.0 \times 10^{-8}$
$0.60$	$24.75 \times 10^{-8}$

In the reaction $A + B \to \text{Products}$,if $B$ is taken in excess,then it is an example of

Similar Questions

For a reaction whose rate expression is: Rate $= k[A]^{1/2}[B]^{3/2}$,the order would be

Explain the order of reaction for complex reactions by giving examples.

Inversion of cane sugar is an example of $-$

Select the rate law that corresponds to the data shown for the following reaction $A + B \to C$ $Expt. \ No.$ $[A]$ $[B]$ $Initial \ Rate$ $1$ $0.012$ $0.035$ $0.10$ $2$ $0.024$ $0.070$ $0.80$ $3$ $0.024$ $0.035$ $0.10$ $4$ $0.012$ $0.070$ $0.80$

For the decomposition of a compound $AB$ at $600 \ K$,the following data were obtained: $[AB] \ (mol \ dm^{-3})$Rate of decomposition of $AB \ (mol \ dm^{-3} \ s^{-1})$$0.20$$2.75 \times 10^{-8}$$0.40$$11.0 \times 10^{-8}$$0.60$$24.75 \times 10^{-8}$ The order for the decomposition of $AB$ is:

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Select the rate law that corresponds to the data shown for the following reaction $A + B \to C$

$Expt. \ No.$ $[A]$ $[B]$ $Initial \ Rate$

$1$ $0.012$ $0.035$ $0.10$

$2$ $0.024$ $0.070$ $0.80$

$3$ $0.024$ $0.035$ $0.10$

$4$ $0.012$ $0.070$ $0.80$