In the reaction,$2n \ R-X \xrightarrow[\text{Dry ether}]{+2n \ Na} \text{product}$. The product obtained is
- A$n \ \text{Alkene}$
- B$n \ \text{Sodium halide}$
- C$n \ \text{Alcohol}$
- D$n \ \text{Alkane}$
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