In the reaction,$CH_3-COOH$ $\xrightarrow{LiAlH_4} A$ $\xrightarrow{PCl_5} B$ $\xrightarrow{Alc. KOH} C$,the product $C$ is:

Amongst the following compounds, the one which would not respond to iodoform test is

Benzoic acid is less acidic than salicylic acid because of:

Product $(A)$ of the above reaction is

Aspirin is an acetylation product of

$CH_2=CH-CO-OCH_3$ (methyl acrylate,bp $81^\circ C$) + $CH_3-CH_2-CH_2-CH_2-OH$ (n-butyl alcohol,bp $117^\circ C$) $\xrightarrow{TsOH, \Delta} (A)$ (bp $145^\circ C$) + $CH_3OH$ (bp $65^\circ C$). Product $(A)$ of the above reaction is: