In the reaction of $p-$chlorotoluene with $KNH_2$ in liquid $NH_3,$ the major product is :

  • A
    $o-$Toluidine
  • B
    $m-$Toluidine
  • C
    $p-$Toluidine
  • D
    $p-$Chloroaniline

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Number of deactivating groups in the following is $-Cl, -SO_3H, -OH, -NHC_2H_5, -COOCH_3, -CH_3$.

$(i)$ chlorobenzene is mono-nitrated to $M$.
$(ii)$ nitrobenzene is mono-chlorinated to $N$.
$(iii)$ anisole is mono-nitrated to $P$.
$(iv)$ $2-$nitrochlorobenzene is mono-nitrated to $Q$.
Out of $M$,$N$,$P$ and $Q$,the compound that undergoes reaction with $aq. NaOH$ fastest is:

Arrange the following compounds in decreasing order of their rate of $S_NAr$ reaction:
$(i)$ $p$-nitrochlorobenzene
(ii) $m$-nitrochlorobenzene
(iii) $2,4$-dinitrochlorobenzene
(iv) chlorobenzene
$(v)$ $2,4,6$-trinitrochlorobenzene

The strongest ortho-para and strongest meta-directing groups respectively are

The lower reactivity of the chlorine atom in $CH_2 = CH - Cl$ is due to:

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