In the reaction sequence: $CH_2OH-CHOH-CH_2OH$ $\xrightarrow{KHSO_4/\Delta} (X)$ $\xrightarrow{(C_2H_5O)_3Al/\Delta} (Y)$,$(Y)$ will be:
- A$CH_2=CH-CHO$
- B$CH_2=CH-CH_2OH$
- CMixture of $CH_2=CH-COOH$ and $CH_2=CH-CH_2OH$
- D$CH_2=CH-C(=O)-O-CH_2-CH=CH_2$
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Similar Questions
For the sequence of reactions,$A$ $\xrightarrow[{ether}]{{C_2H_5MgI}} B$ $\xrightarrow{{H_2O/H^{+}}}$ tert-Pentyl alcohol. The compound $A$ in the sequence is
Medium
View SolutionWhich of the following carbonyl compounds forms the most stable hydrate when $H_2O$ is added across the $C=O$ group?
Match the example given in Column-$I$ with the name of the reaction in Column-$II$.
Column-$I$ (Example) Column-$II$ (Reaction) $(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$ $(1)$ Friedel-Crafts acylation $(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$ $(2)$ $HVZ$ reaction $(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$ $(3)$ Aldol condensation $(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$ $(4)$ Cannizzaro's reaction $(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$ $(5)$ Rosenmund's reduction $(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$ $(6)$ Stephen's reaction
| Column-$I$ (Example) | Column-$II$ (Reaction) |
|---|---|
| $(A)$ $CH_3COCl + H_2 \xrightarrow{Pd-C/BaSO_4} CH_3CHO$ | $(1)$ Friedel-Crafts acylation |
| $(B)$ $C_6H_5CHO \xrightarrow{NaOH} C_6H_5CH_2OH + C_6H_5COONa$ | $(2)$ $HVZ$ reaction |
| $(C)$ $C_6H_6 + CH_3COCl \xrightarrow{AlCl_3} C_6H_5COCH_3$ | $(3)$ Aldol condensation |
| $(D)$ $R-CH_2COOH \xrightarrow{Br_2/Red P} R-CH(Br)COOH$ | $(4)$ Cannizzaro's reaction |
| $(E)$ $CH_3-CN \xrightarrow{SnCl_2/HCl, H_2O/H^+} CH_3-CHO$ | $(5)$ Rosenmund's reduction |
| $(F)$ $2CH_3CHO \xrightarrow{NaOH} CH_3-CH=CH-CHO$ | $(6)$ Stephen's reaction |
Medium
View SolutionThe aldehydes which will not form a single Grignard product with one equivalent of Grignard reagent are:
$(a)$ Benzaldehyde
$(b)$ $4$-Formylbenzoic acid
$(c)$ $4$-Methoxybenzaldehyde
$(d)$ $4$-(Hydroxymethyl)benzaldehyde
$(a)$ Benzaldehyde
$(b)$ $4$-Formylbenzoic acid
$(c)$ $4$-Methoxybenzaldehyde
$(d)$ $4$-(Hydroxymethyl)benzaldehyde
DifficultJEE MAIN 2019
View SolutionIdentify $(A)$ in the following reaction sequence:
$\mathop {(A)}\limits_{\text{gives positive iodoform Test}}$ $\xrightarrow[(ii) H^{+}, H_2O, (iii) \text{conc. } H_2SO_4/\Delta ]{(i) CH_3MgBr} (B)$ $\xrightarrow{O_3/Zn, H_2O}$
$\mathop {(A)}\limits_{\text{gives positive iodoform Test}}$ $\xrightarrow[(ii) H^{+}, H_2O, (iii) \text{conc. } H_2SO_4/\Delta ]{(i) CH_3MgBr} (B)$ $\xrightarrow{O_3/Zn, H_2O}$
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