In the standing wave shown,particles at the positions $A$ and $B$ have a phase difference of

The distance between the nearest node and antinode in a stationary wave is

The ends of a stretched wire of length $L$ are fixed at $x = 0$ and $x = L.$ In one experiment,the displacement of the wire is ${y_1} = A\sin (\pi x/L)\sin \omega t$ and energy is ${E_1}$,and in another experiment its displacement is ${y_2} = A\sin (2\pi x/L)\sin 2\omega t$ and energy is ${E_2}$. Then

What will be the phase difference of particles in successive intervals of stationary waves?

The equation of a stationary wave is $y = 20 \sin(\pi x) \cos(\omega t)$,where $x$ and $y$ are in meters and $t$ is in seconds. The distance between a node and its adjacent antinode is (in $\text{ cm}$)

Give the distance between consecutive nodes and antinodes in terms of wavelength $\lambda$.