In the successive emission of alpha- and beta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The nuclear reaction is: ${}^{238}_{92}U \longrightarrow {}^{206}_{82}Pb + m({}^{4}_{2}He) + n({}^{0}_{-1}e)$.Comparing the mass numbers on both s

Vedclass · Accepted Answer

$8 \alpha, 6 \beta$

Vedclass · Answer

(A) The nuclear reaction is: ${}^{238}_{92}U \longrightarrow {}^{206}_{82}Pb + m({}^{4}_{2}He) + n({}^{0}_{-1}e)$.Comparing the mass numbers on both sides: $238 = 206 + 4m$ $\Rightarrow 4m = 32$ $\Rightarrow m = 8$.Comparing the atomic numbers on both sides: $92 = 82 + 2m - n$.Substituting $m = 8$: $92 = 82 + 2(8) - n$ $\Rightarrow 92 = 82 + 16 - n$ $\Rightarrow 92 = 98 - n$ $\Rightarrow n = 6$.Therefore,$8$ $\alpha$-particles and $6$ $\beta$-particles are emitted.

In the successive emission of $\alpha$- and $\beta$-particles,the number of $\alpha$- and $\beta$-particles that should be emitted for the conversion of ${}^{238}_{92}U$ to ${}^{206}_{82}Pb$ are:

Similar Questions

The fuel used in an atomic pile is

Radioactive disintegration differs from a chemical change in being

Which one of the following statements is correct?

In a nuclear reactor,the chain reaction is controlled by introducing:

When nuclear energy is intended to be harnessed for the generation of electricity,the potentially destructive neutrons released in a nuclear reactor are absorbed by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module