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(B) The energy of an electron in the $n$-th orbit of a hydrogen-like atom is given by $E_n = -13.6 \frac{Z^2}{n^2} 	ext{ eV}$.Thus,$E \propto \frac{Z

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$\frac{36 E}{25}$

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(B) The energy of an electron in the $n$-th orbit of a hydrogen-like atom is given by $E_n = -13.6 \frac{Z^2}{n^2} 	ext{ eV}$.Thus,$E \propto \frac{Z^2}{n^2}$.For the hydrogen atom $(Z_H = 1)$ in the third orbit $(n_H = 3)$,the energy is $E = k \frac{1^2}{3^2} = \frac{k}{9}$,where $k$ is a constant.For the helium ion $(Z_{He} = 2)$ in the fifth orbit $(n_{He} = 5)$,the energy $E_{He}$ is given by $E_{He} = k \frac{2^2}{5^2} = \frac{4k}{25}$.Dividing the two expressions: $\frac{E_{He}}{E} = \frac{4k/25}{k/9} = \frac{4}{25} 	imes 9 = \frac{36}{25}$.Therefore,$E_{He} = \frac{36}{25} E$.

In the third orbit of a hydrogen atom,the energy of an electron is $E$. In the fifth orbit of a helium ion $(Z=2)$,the energy of an electron will be:

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