In the two elements, { }_{Z_1} A^{M_1} and { | vedclass

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Question

(A) Given, ${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$.Here, $M_1 
eq M_2$ and $Z_1 
eq Z_2$ $(M = 	ext{atomic weight}, Z = 	ext{atomic number})$.

Vedclass · Accepted Answer

isotonic

Vedclass · Answer

(A) Given, ${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$.Here, $M_1 
eq M_2$ and $Z_1 
eq Z_2$ $(M = 	ext{atomic weight}, Z = 	ext{atomic number})$.But, $M_1 - Z_1 = M_2 - Z_2$.We know that $	ext{atomic weight} = 	ext{number of protons} + 	ext{number of neutrons}$ and $	ext{atomic number} = 	ext{number of protons}$.Therefore, $	ext{number of neutrons} = 	ext{atomic weight} - 	ext{atomic number}$.Since $M_1 - Z_1$ and $M_2 - Z_2$ represent the number of neutrons in elements $A$ and $B$ respectively, and they are equal, these elements have the same number of neutrons.Species having the same number of neutrons are known as isotones.Thus, these elements are isotonic.

In the two elements, ${ }_{Z_1} A^{M_1}$ and ${ }_{Z_2} B^{M_2}$, the following relations are true. $M_1 \neq M_2$ and $Z_1 \neq Z_2$ but $M_1-Z_1=M_2-Z_2$. These elements are ($M$ is atomic weight, $Z$ is atomic number)

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