In this circuit,the value of I_2 is (in A) | vedclass

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(C) The three resistors $10 \Omega$,$15 \Omega$,and $30 \Omega$ are connected in parallel. The equivalent resistance $R_{eq}$ is given by:$\frac{1}{R_

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$0.4$

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(C) The three resistors $10 \Omega$,$15 \Omega$,and $30 \Omega$ are connected in parallel. The equivalent resistance $R_{eq}$ is given by:$\frac{1}{R_{eq}} = \frac{1}{10} + \frac{1}{15} + \frac{1}{30} = \frac{3+2+1}{30} = \frac{6}{30} = \frac{1}{5} \Omega^{-1}$So,$R_{eq} = 5 \Omega$.The total voltage $V$ across the parallel combination is:$V = I 	imes R_{eq} = 1.2 	imes 5 = 6 \ V$.Since the resistors are in parallel,the voltage across each resistor is the same $(6 \ V)$.Therefore,the current $I_2$ through the $15 \Omega$ resistor is:$I_2 = \frac{V}{R_2} = \frac{6}{15} = 0.4 \ A$.

In this circuit,the value of $I_2$ is (in $A$)

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