In water saturated air,the mole fraction of w | vedclass

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(C) The total pressure of the saturated air is the sum of the partial pressure of dry air and the partial pressure of water vapour.Given,the mole frac

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$1.176$

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(C) The total pressure of the saturated air is the sum of the partial pressure of dry air and the partial pressure of water vapour.Given,the mole fraction of water vapour,$X_{H_{2}O} = 0.02$.The mole fraction of dry air,$X_{dry\;air} = 1 - X_{H_{2}O} = 1 - 0.02 = 0.98$.The partial pressure of a component is given by $P_{i} = X_{i} 	imes P_{total}$.Therefore,the partial pressure of dry air $= X_{dry\;air} 	imes P_{total} = 0.98 	imes 1.2 \; atm = 1.176 \; atm$.

In water saturated air,the mole fraction of water vapour is $0.02$. If the total pressure of the saturated air is $1.2 \; atm$,the partial pressure of dry air is .....$atm$.

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