In which of the following is the bond angle m | vedclass

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(B) The bond angle depends on the hybridization and the presence of lone pairs on the central atom.$NH_4^+$ has $sp^3$ hybridization with $0$ lone pai

Vedclass · Accepted Answer

$NH_4^+$

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(B) The bond angle depends on the hybridization and the presence of lone pairs on the central atom.$NH_4^+$ has $sp^3$ hybridization with $0$ lone pairs,resulting in a perfect tetrahedral geometry with a bond angle of $109.5^\circ$.$NH_3$ has $sp^3$ hybridization with $1$ lone pair,resulting in a bond angle of $107^\circ$.$PH_3$ has a bond angle of approximately $93.5^\circ$ due to the lack of hybridization (Drago's rule).$SCl_2$ has $sp^3$ hybridization with $2$ lone pairs,resulting in a bond angle of approximately $103^\circ$.Therefore,the bond angle is maximum in $NH_4^+$.

$List-I$ (Compound)	$List-II$ (Shape)
$A$. $BrF_5$	$I$. bent
$B$. $[CrF_6]^{3-}$	$II$. square pyramidal
$C$. $O_3$	$III$. trigonal bipyramidal
$D$. $PCl_5$	$IV$. octahedral

In which of the following is the bond angle maximum?

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Match $List-I$ with $List-II$.
$List-I$ (Compound) $List-II$ (Shape)
$A$. $BrF_5$ $I$. bent
$B$. $[CrF_6]^{3-}$ $II$. square pyramidal
$C$. $O_3$ $III$. trigonal bipyramidal
$D$. $PCl_5$ $IV$. octahedral

Choose the correct answer from the options given below.

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