In which case does the heterolysis of the car | vedclass

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(B) The stability of a carbocation is determined by factors like resonance,inductive effect,and hyperconjugation. In the case of $2$-chlorotetrahydrop

Vedclass · Accepted Answer

$2-$chlorotetrahydropyran

Vedclass · Answer

(B) The stability of a carbocation is determined by factors like resonance,inductive effect,and hyperconjugation. In the case of $2$-chlorotetrahydropyran,the heterolysis of the $C-Cl$ bond generates a carbocation adjacent to an oxygen atom. The lone pair of electrons on the oxygen atom can delocalize into the vacant $p$-orbital of the carbocation,forming an oxocarbenium ion. This structure is highly stable because every atom,including the carbon,achieves a complete octet configuration. Therefore,$2$-chlorotetrahydropyran forms the most stable carbocation among the given options.

In which case does the heterolysis of the carbon-chlorine bond lead to the most stable carbocation?

Similar Questions

Among the following, which is the most stable carbocation?

Arrange the following carbanions in the decreasing order of their stability:
$(1) CH_3-CH_2^-, (2) CH_2=CH^-, (3) HC \equiv C^-$

Which of the following is the least stable carbocation?

The order of stability of carbonium ions is:

Intermediates formed in the reactions $P$ and $Q$ are:
$P: CH_3-CH=CH_2 \xrightarrow{HCl}$
$Q: CH_3-CH=CH_2 \xrightarrow[\text{Peroxide}]{HCl}$

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