In which hybridisation is an angular shape no | vedclass

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(A) For a molecule to have an angular (bent) shape,it must have at least one lone pair on the central atom and be bonded to two other atoms.In $sp$ hy

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$sp$

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(A) For a molecule to have an angular (bent) shape,it must have at least one lone pair on the central atom and be bonded to two other atoms.In $sp$ hybridisation,the geometry is linear with a bond angle of $180^{\circ}$. Even with lone pairs,the arrangement remains linear (e.g.,$XeF_2$ is linear,though it has $sp^3d$ hybridisation,but for simple $sp$ systems like $BeCl_2$,it is linear).In $sp^2$ hybridisation,the geometry is trigonal planar. If one lone pair is present,the shape becomes angular (e.g.,$SO_2$,$SnCl_2$).In $sp^3$ hybridisation,the geometry is tetrahedral. If two lone pairs are present,the shape becomes angular (e.g.,$H_2O$).Therefore,an angular shape is not possible in $sp$ hybridisation because the bond angle is fixed at $180^{\circ}$.

In which hybridisation is an angular shape not possible?

Similar Questions

Predict the hybridization of each carbon in the molecule of the organic compound given below. Also,indicate the total number of sigma $(\sigma)$ and pi $(\pi)$ bonds in this molecule.
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