In which of the following arrangements,the se | vedclass

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(B) The correct order for basic strength of group $15$ hydrides is $NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$. As the size of the central atom increases,th

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$NH_3 < PH_3 < AsH_3 < SbH_3$ : increasing basic strength

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(B) The correct order for basic strength of group $15$ hydrides is $NH_3 > PH_3 > AsH_3 > SbH_3 > BiH_3$. As the size of the central atom increases,the electron density on the central atom decreases,making it less available for donation,thus decreasing basic strength. Therefore,the sequence $NH_3 < PH_3 < AsH_3 < SbH_3$ is incorrect as it represents increasing basic strength,whereas it should be decreasing.

In which of the following arrangements,the sequence is not strictly according to the property written against it?

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