In which of the following complex species,Del | vedclass

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(D) The magnetic moment is given by $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.Given $\mu = \sqrt{3} \ B.M.$,we have $

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$[Fe(CN)_6]^{3-}$

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(D) The magnetic moment is given by $\mu = \sqrt{n(n+2)} \ B.M.$,where $n$ is the number of unpaired electrons.Given $\mu = \sqrt{3} \ B.M.$,we have $\sqrt{n(n+2)} = \sqrt{3}$,which implies $n = 1$.For $\Delta_0 > P$,the complex must be a low-spin complex.Let's analyze the options:$A$: $[Co(H_2O)_4(NH_3)_2]^{3+}$: $Co^{3+}$ is $d^6$. With strong field ligands,it forms a low-spin complex with $t_{2g}^6 e_g^0$,so $n = 0$.$B$: $[RhF_6]^{3-}$: $Rh^{3+}$ is $4d^6$. $4d$ and $5d$ series elements always form low-spin complexes,but $F^-$ is a weak field ligand. However,$Rh^{3+}$ is $d^6$,so $t_{2g}^6 e_g^0$,$n = 0$.$C$: $[Cr(CO)_6]$: $Cr^0$ is $d^6$. $CO$ is a strong field ligand,forming a low-spin complex with $t_{2g}^6 e_g^0$,$n = 0$.$D$: $[Fe(CN)_6]^{3-}$: $Fe^{3+}$ is $d^5$. $CN^-$ is a strong field ligand,forcing pairing. The configuration is $t_{2g}^5 e_g^0$,resulting in $n = 1$ unpaired electron. Thus,$\mu = \sqrt{1(1+2)} = \sqrt{3} \ B.M.$ and $\Delta_0 > P$.

In which of the following complex species,$\Delta_0 > P$ (pairing energy) with magnetic moment $\sqrt{3} \ B.M.$?

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