In which of the following compounds does chlo | vedclass

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(D) To find the oxidation state of chlorine $(Cl)$ in each compound,we use the rules for oxidation numbers:$1$. In $KCl$,the oxidation state of $K$ is

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$HClO_4$

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(D) To find the oxidation state of chlorine $(Cl)$ in each compound,we use the rules for oxidation numbers:$1$. In $KCl$,the oxidation state of $K$ is $+1$. Let the oxidation state of $Cl$ be $x$. So,$1 + x = 0$,which gives $x = -1$.$2$. In $HClO$,the oxidation state of $H$ is $+1$ and $O$ is $-2$. Let the oxidation state of $Cl$ be $x$. So,$1 + x - 2 = 0$,which gives $x = +1$.$3$. In $HClO_2$,the oxidation state of $H$ is $+1$ and $O$ is $-2$. Let the oxidation state of $Cl$ be $x$. So,$1 + x + 2(-2) = 0$,which gives $1 + x - 4 = 0$,so $x = +3$.$4$. In $HClO_4$,the oxidation state of $H$ is $+1$ and $O$ is $-2$. Let the oxidation state of $Cl$ be $x$. So,$1 + x + 4(-2) = 0$,which gives $1 + x - 8 = 0$,so $x = +7$.Comparing the values: $-1, +1, +3, +7$. The highest oxidation state is $+7$ in $HClO_4$.

In which of the following compounds does chlorine have the highest oxidation state?

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