In which of the following compounds is the oc | vedclass

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(C) The octet status for the given compounds is as follows:$(i)$ $Al_2Cl_6$: In this dimer,$Al$ atoms complete their octet by coordinate bonding from

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$C - IC - C - IC - IC$

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(C) The octet status for the given compounds is as follows:$(i)$ $Al_2Cl_6$: In this dimer,$Al$ atoms complete their octet by coordinate bonding from $Cl$ lone pairs. Thus,it is $C$.(ii) $Al_2(CH_3)_6$: This contains $3c-2e^-$ bonds (electron-deficient),so the octet is incomplete. Thus,it is $IC$.(iii) $AlF_3$: This is an ionic compound where $Al^{3+}$ and $F^-$ ions both have complete octets $(2s^2 2p^6)$. Thus,it is $C$.(iv) Dimer of $BeCl_2$: The $Be$ atom is electron-deficient even in the dimer form. Thus,it is $IC$.$(v)$ Dimer of $BeH_2$: This contains $3c-2e^-$ bonds,making it electron-deficient. Thus,it is $IC$.Therefore,the sequence is $C - IC - C - IC - IC$.

In which of the following compounds is the octet complete $(C)$ or incomplete $(IC)$ for all atoms?
$Al_2Cl_6$ $-$ $Al_2(CH_3)_6$ $-$ $AlF_3$ $-$ Dimer of $BeCl_2$ $-$ Dimer of $BeH_2$
(Note: $C$ for complete octet and $IC$ for incomplete octet.)

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In which of the following compounds is the octet complete $(C)$ or incomplete $(IC)$ for all atoms?$Al_2Cl_6$ $-$ $Al_2(CH_3)_6$ $-$ $AlF_3$ $-$ Dimer of $BeCl_2$ $-$ Dimer of $BeH_2$(Note: $C$ for complete octet and $IC$ for incomplete octet.)