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(C) Let us analyze the geometry of each species:$(a)$ $ClF_3$ is $T$-shaped (planar) and $ClF_4^{-}$ is square planar (planar). No change in planarity

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only $b$

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(C) Let us analyze the geometry of each species:$(a)$ $ClF_3$ is $T$-shaped (planar) and $ClF_4^{-}$ is square planar (planar). No change in planarity.$(b)$ $NH_2^{-}$ is $V$-shaped (planar) and $NH_4^{+}$ is tetrahedral (non-planar). Thus,it changes from planar to non-planar.$(c)$ $I_3^{+}$ is angular (planar) and $I_3^{-}$ is linear (planar). No change in planarity.$(d)$ $SO_2$ is angular (planar) and $SO_3$ is trigonal planar (planar). No change in planarity.Therefore,only $(b)$ involves a change from a planar to a non-planar compound.

$I. SnCl_2$	$II. BeF_2$
$III. SO_2$	$IV. NO_2^+$
$V. C_2H_2$

In which of the following conversions does a planar compound change into a non-planar compound?
$(a)$ $ClF_3 \rightarrow ClF_4^{-}$
$(b)$ $NH_2^{-} \rightarrow NH_4^{+}$
$(c)$ $I_3^{+} \rightarrow I_3^{-}$
$(d)$ $SO_2 \rightarrow SO_3$

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In which of the following conversions does a planar compound change into a non-planar compound?$(a)$ $ClF_3 \rightarrow ClF_4^{-}$$(b)$ $NH_2^{-} \rightarrow NH_4^{+}$$(c)$ $I_3^{+} \rightarrow I_3^{-}$$(d)$ $SO_2 \rightarrow SO_3$