In which of the following molecules is the el | vedclass

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(D) Let us analyze each option:$A$. In $CH_3COOH$,the carbonyl oxygen $(II)$ has higher electron density than the hydroxyl oxygen $(I)$ because the hy

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Lactone $(I)$ and Carbonate $(II)$ where $II > I$

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(D) Let us analyze each option:$A$. In $CH_3COOH$,the carbonyl oxygen $(II)$ has higher electron density than the hydroxyl oxygen $(I)$ because the hydroxyl oxygen donates its lone pair into the carbonyl group via resonance,making the carbonyl oxygen more electron-rich. Thus,$II > I$ is correct.$B$. In $N$-cyclohexylacetamide $(I)$,the lone pair on nitrogen is delocalized into the carbonyl group. In $N$-phenylacetamide $(II)$,the lone pair on nitrogen is delocalized into both the carbonyl group and the benzene ring. Thus,the electron density on the nitrogen (and consequently the oxygen) is higher in $I$ than in $II$. Thus,$I > II$ is correct.$C$. In $CH_3NO_2$,the nitro group has one $N=O$ bond and one $N-O^-$ bond. The oxygen with the negative charge $(II)$ has significantly higher electron density than the neutral carbonyl-like oxygen $(I)$. Thus,$II > I$ is correct.$D$. In the lactone $(I)$,the oxygen is part of a cyclic ester. In the carbonate $(II)$,there are two oxygen atoms attached to the central carbon,both donating lone pairs via resonance. The electron density on the oxygen atoms in the carbonate is lower due to the increased delocalization compared to the lactone. Thus,$I > II$ is the correct relationship,making $II > I$ incorrect.

In which of the following molecules is the electron density on the oxygen atom $NOT$ correctly mentioned?

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