In which of the following options,the molecul | vedclass

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(D) To determine the bond angles,we look at the hybridization and lone pairs of the central atoms: $1$. $H_2O$: $sp^3$ hybridization,$2$ lone pairs,bo

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$H_2 O < NH_3 < O_3 < SO_2$

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(D) To determine the bond angles,we look at the hybridization and lone pairs of the central atoms: $1$. $H_2O$: $sp^3$ hybridization,$2$ lone pairs,bond angle $\approx 104.5^\circ$. $2$. $NH_3$: $sp^3$ hybridization,$1$ lone pair,bond angle $\approx 107^\circ$. $3$. $O_3$: $sp^2$ hybridization,$1$ lone pair,bond angle $\approx 117^\circ$. $4$. $SO_2$: $sp^2$ hybridization,$1$ lone pair,bond angle $\approx 119^\circ$. Comparing these,the increasing order is $H_2O Thus,the correct option is $D$.

List-$I$	List-$II$
$(1)$ ${H_3O^+}$	$(A)$ Linear
$(2)$ ${HC \equiv CH}$	$(B)$ Angular
$(3)$ ${ClO_2^-}$	$(C)$ Tetrahedral
$(4)$ ${NH_4^+}$	$(D)$ Trigonal bipyramidal
	$(E)$ Pyramidal

In which of the following options,the molecules are correctly arranged in the increasing order of their bond angles?

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The increasing order of $O-N-O$ bond angle in the species $NO_2$, $NO_2^+$ and $NO_2^-$ is

Match the species given in List-$I$ with their correct geometric shapes given in List-$II$.

List-$I$ List-$II$

$(1)$ ${H_3O^+}$ $(A)$ Linear

$(2)$ ${HC \equiv CH}$ $(B)$ Angular

$(3)$ ${ClO_2^-}$ $(C)$ Tetrahedral

$(4)$ ${NH_4^+}$ $(D)$ Trigonal bipyramidal

$(E)$ Pyramidal

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What is the shape of $ClO_3^-$?

Which of the following sequences represents the correct increasing order of bond angles in the given molecules?

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