In which of the following,orbitals are correc | vedclass

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(C) For multi-electron atoms,the energy of the orbitals increases with an increase in their $(n+l)$ value.According to the $(n+l)$ rule:For $5p$: $n=5

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$5p < 6s < 4f < 5d$

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(C) For multi-electron atoms,the energy of the orbitals increases with an increase in their $(n+l)$ value.According to the $(n+l)$ rule:For $5p$: $n=5, l=1$,$(n+l) = 6$For $6s$: $n=6, l=0$,$(n+l) = 6$For $4f$: $n=4, l=3$,$(n+l) = 7$For $5d$: $n=5, l=2$,$(n+l) = 7$When $(n+l)$ values are equal,the orbital with the lower $n$ value has lower energy.Comparing $5p$ and $6s$: $5p$ has lower $n$,so $5p Comparing $4f$ and $5d$: $4f$ has lower $n$,so $4f Thus,the correct increasing order of energy is: $5p < 6s < 4f < 5d$.

In which of the following,orbitals are correctly arranged in the increasing order of their energies?

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