In which of the following processes does the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To determine the change in bond order and magnetic nature,we analyze the molecular orbital configurations:$1$. For $O_2 (16e^-)$: Bond order = $2.

Vedclass · Accepted Answer

$N_2^+ 	o N_2^-$

Vedclass · Answer

(B) To determine the change in bond order and magnetic nature,we analyze the molecular orbital configurations:$1$. For $O_2 (16e^-)$: Bond order = $2.0$,Paramagnetic. For $O_2^+ (15e^-)$: Bond order = $2.5$,Paramagnetic. (Both change).$2$. For $N_2^+ (13e^-)$: Bond order = $2.5$,Paramagnetic. For $N_2^- (15e^-)$: Bond order = $2.5$,Paramagnetic. (Bond order and magnetic nature remain unchanged).$3$. For $NO (15e^-)$: Bond order = $2.5$,Paramagnetic. For $NO^+ (14e^-)$: Bond order = $3.0$,Diamagnetic. (Both change).$4$. For $CO (14e^-)$: Bond order = $3.0$,Diamagnetic. For $CO^+ (13e^-)$: Bond order = $2.5$,Paramagnetic. (Both change).Thus,the process $N_2^+ 	o N_2^-$ maintains both properties.

In which of the following processes does the value of bond order and magnetic nature not change?

Similar Questions

What is the bond order in $N_{2}$ molecule?

The oxygen molecule $(O_2)$ exhibits which of the following magnetic properties?

What is the bond order of $O_2^-$ (in $.5$)?

Explain the energy level diagram for molecular orbitals formed by $1s$ orbitals.

Among $KO_2$,$NO_2^-$,$BaO_2$ and $NO_2^+$,an unpaired electron is present in:

Vedclass Test Series

Exam Paper Generator

Online Exam Module