In which of the following reactions does H_2O | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) reducing agent is a substance that loses electrons and undergoes oxidation.In reaction $(II)$,$H_2O_2 	o O_2 + 2H^{+} + 2e^-$,$H_2O_2$ loses elec

Vedclass · Accepted Answer

$II$ and $IV$

Vedclass · Answer

(D) reducing agent is a substance that loses electrons and undergoes oxidation.In reaction $(II)$,$H_2O_2 	o O_2 + 2H^{+} + 2e^-$,$H_2O_2$ loses electrons and is oxidized,thus acting as a reducing agent.In reaction $(IV)$,$H_2O_2 + 2OH^{-} 	o O_2 + 2H_2O + 2e^-$,$H_2O_2$ loses electrons and is oxidized,thus acting as a reducing agent.In reactions $(I)$ and $(III)$,$H_2O_2$ gains electrons and is reduced,acting as an oxidizing agent.Therefore,$H_2O_2$ acts as a reducing agent in reactions $(II)$ and $(IV)$.

In which of the following reactions does $H_2O_2$ act as a reducing agent?
$(I)$ $H_2O_2 + 2H^{+} + 2e^- \to 2H_2O$
$(II)$ $H_2O_2 \to O_2 + 2H^{+} + 2e^-$
$(III)$ $H_2O_2 + 2e^- \to 2OH^{-}$
$(IV)$ $H_2O_2 + 2OH^{-} \to O_2 + 2H_2O + 2e^-$

Similar Questions

The dihedral angles in gaseous and solid phases of $H_2O_2$ molecule respectively are

Which of the following is known as 'Oxone'?

The last drop of water can be removed from $H_2O_2$ by :-

$Hydrogen$ $peroxide$ is reduced by:

The strength of $H_2O_2$ sample available from market is $8.32\% \ W/V$. The volume and molar concentration of this sample are ......... and ........ respectively.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

In which of the following reactions does $H_2O_2$ act as a reducing agent?$(I)$ $H_2O_2 + 2H^{+} + 2e^- \to 2H_2O$$(II)$ $H_2O_2 \to O_2 + 2H^{+} + 2e^-$$(III)$ $H_2O_2 + 2e^- \to 2OH^{-}$$(IV)$ $H_2O_2 + 2OH^{-} \to O_2 + 2H_2O + 2e^-$