In which of the following reactions will hydr | vedclass

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(D) Alcohols react with active metals like $Na$,$K$,and $Al$ to liberate hydrogen gas $(H_2)$.For example: $2CH_3-CH_2-OH + 2Na \rightarrow 2CH_3-CH_2

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$CH_3-CH(CH_3)-OH \xrightarrow{CH_3MgBr}$

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(D) Alcohols react with active metals like $Na$,$K$,and $Al$ to liberate hydrogen gas $(H_2)$.For example: $2CH_3-CH_2-OH + 2Na \rightarrow 2CH_3-CH_2-ONa + H_2 \uparrow$.However,when an alcohol reacts with a Grignard reagent $(CH_3MgBr)$,an acid-base reaction occurs where the acidic hydrogen of the alcohol is abstracted by the alkyl group of the Grignard reagent to form an alkane.Reaction: $CH_3-CH(OH)-CH_3 + CH_3MgBr \rightarrow CH_4 \uparrow + CH_3-CH(OMgBr)-CH_3$.Here,methane $(CH_4)$ gas is evolved instead of hydrogen gas.

In which of the following reactions will hydrogen gas not be evolved?

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