In which of the following species is the unde | vedclass

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(B) To determine the hybridisation of the underlined carbon atom,we count the number of sigma bonds and lone pairs attached to it.$(A)$ In $CH_3-\unde

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$CH_3-\underline{C}H_2OH$

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(B) To determine the hybridisation of the underlined carbon atom,we count the number of sigma bonds and lone pairs attached to it.$(A)$ In $CH_3-\underline{C}OOH$,the underlined carbon is bonded to one oxygen by a double bond and one oxygen by a single bond,making it $sp^2$ hybridized.$(B)$ In $CH_3-\underline{C}H_2OH$,the underlined carbon is bonded to four atoms (one $C$,two $H$,and one $O$) via single bonds. Since it has $4$ sigma bonds and $0$ lone pairs,it is $sp^3$ hybridized.$(C)$ In $CH_3-\underline{C}OCH_3$,the underlined carbon is part of a carbonyl group $(C=O)$,making it $sp^2$ hybridized.$(D)$ In $CH_2=\underline{C}H-CH_3$,the underlined carbon is bonded to one $C$ via a double bond and one $C$ via a single bond,making it $sp^2$ hybridized.Therefore,the correct option is $B$.

In which of the following species is the underlined carbon having $sp^3$ hybridisation?

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Among the following compounds,which have more than one type of hybridization for carbon atoms?
$(i) CH_3CH_2CH_2CH_3$
$(ii) CH_3-CH=CH-CH_3$
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$(iv) HC\equiv CH$

Amongst the given options,the compound$(s)$ in which all the atoms are in one plane in all the possible conformations (if any),is (are):
$(A)$ $CH_2=CH-CH=CH_2$
$(B)$ $HC\equiv C-CH=CH_2$
$(C)$ $H_2C=C=O$
$(D)$ $H_2C=C=CH_2$

In the structure $CH_2 = CH - C \equiv CH$,what are the hybridization states of the carbon atoms that are connected to each other by a single bond?

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