In which one of the following combinations (a | vedclass

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(D) The basic chromosome number of wheat is $x = 7$. Hexaploid wheat $(6x)$ contains $42$ chromosomes $(6 	imes 7 = 42)$. $1$. Monosomic: One chromos

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$41, 21, 40, 43$

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(D) The basic chromosome number of wheat is $x = 7$. Hexaploid wheat $(6x)$ contains $42$ chromosomes $(6 	imes 7 = 42)$. $1$. Monosomic: One chromosome is missing from the diploid set $(2n-1)$. Since $2n = 42$, monosomic is $42 - 1 = 41$. $2$. Haploid: Half the number of chromosomes in the somatic cell $(n)$. Here, $n = 42 / 2 = 21$. $3$. Nullisomic: One entire pair of chromosomes is missing $(2n-2)$. Here, $42 - 2 = 40$. $4$. Trisomic: One extra chromosome is present in the diploid set $(2n+1)$. Here, $42 + 1 = 43$. Thus, the correct sequence is $41, 21, 40, 43$.

In which one of the following combinations $(a-d)$ of the number of chromosomes is the present day hexaploid wheat correctly represented?

Combination Monosomic,Haploid,Nullisomic,Trisomic

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In which one of the following combinations $(a-d)$ of the number of chromosomes is the present day hexaploid wheat correctly represented? Combination Monosomic,Haploid,Nullisomic,Trisomic