In which pair is the second ion more stable than the first?

  • A
    $(i)$ and $(ii)$
  • B
    $(ii)$ and $(iii)$
  • C
    $(ii)$ and $(iv)$
  • D
    $(iii)$ and $(iv)$

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$p$ will be

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Match the following columns and select the correct option.
List-$I$ (Carbocation) List-$II$ (Type)
$A$. $CH_3-C^{+}(CH_3)-CH_3$ $I$. Secondary carbocation
$B$. $CH_3-C^{+}H-CH_3$ $II$. Methyl carbocation
$C$. $CH_3-CH_2^+$ $III$. Primary carbocation
$D$. $CH_3^+$ $IV$. Tertiary carbocation

$CH_3-C(CH_3)_2-CH_2-CH_2^+ \to CH_3-C^+(CH_3)-CH(CH_3)-CH_3$
How many $H^-$ shifts are involved in the above rearrangement?

Arrange the following carbanions in the order of their stability:
$i$. $RC \equiv C^{\ominus}$
$ii$. $C_6H_5^{\ominus}$
$iii$. $R_2C = CH^{\ominus}$
$iv$. $R_3C - CH_2^{\ominus}$

For the given reaction,the total number of possible products formed by the tertiary carbocation of $A$ is $.........$.

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