In which of the following will benzoic acid n | vedclass

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(D) Let us analyze each reaction:$(A)$ Propylbenzene $(Ph-CH_2-CH_2-CH_3)$ on oxidation with alkaline $KMnO_4$ followed by acidification gives benzoic

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Benzamide reacting with $NaOH/Br_2$.

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(D) Let us analyze each reaction:$(A)$ Propylbenzene $(Ph-CH_2-CH_2-CH_3)$ on oxidation with alkaline $KMnO_4$ followed by acidification gives benzoic acid $(Ph-COOH)$. This is a standard reaction for alkylbenzenes with at least one benzylic hydrogen.$(B)$ Grignard reagent $(Ph-MgX)$ reacts with $CO_2$ to form a carboxylate salt,which upon hydrolysis gives benzoic acid $(Ph-COOH)$.$(C)$ Acetophenone $(Ph-CO-CH_3)$ on oxidation with $H_2CrO_4$ (Jones reagent) or other strong oxidants typically does not yield benzoic acid as the major product under standard conditions; it is generally resistant to oxidation at the ketone group unless harsh conditions are used to cleave the bond.$(D)$ Benzamide $(Ph-CONH_2)$ reacts with $NaOH/Br_2$ (Hofmann bromamide degradation) to form aniline $(Ph-NH_2)$,not benzoic acid.Therefore,both $(C)$ and $(D)$ do not form benzoic acid as a major product. However,in the context of standard textbook questions,the Hofmann degradation $(D)$ is a classic example of a reaction that produces an amine,not an acid. Given the options,$(D)$ is the most definitive case where benzoic acid is not formed.

In which of the following will benzoic acid not be formed as a major product?

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