In Williamson synthesis of mixed ether having | vedclass

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(B) In Williamson synthesis,the reaction between an alkoxide ion and an alkyl halide follows the $S_N2$ mechanism.For ether formation,the alkyl halide

Vedclass · Accepted Answer

Alkene will be the main product.

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(B) In Williamson synthesis,the reaction between an alkoxide ion and an alkyl halide follows the $S_N2$ mechanism.For ether formation,the alkyl halide should ideally be primary.If a tertiary $(3^\circ)$ alkyl halide is used,the alkoxide ion (which is a strong base) promotes elimination $(E2)$ over substitution $(S_N2)$ due to steric hindrance.Consequently,an alkene is formed as the major product instead of an ether.

In Williamson synthesis of mixed ether having a primary and a tertiary alkyl group,if a tertiary halide is used,then:

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