In Young's double-slit experiment,both slits | vedclass

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(C) In Young's double-slit experiment,the fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength

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The pattern gets less bright and farther apart.

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(C) In Young's double-slit experiment,the fringe width $\beta$ is given by the formula $\beta = \frac{\lambda D}{d}$,where $\lambda$ is the wavelength of light,$D$ is the distance between the slits and the screen,and $d$ is the distance between the two slits.As the viewing screen is moved farther from the slits,the distance $D$ increases.Since $\beta \propto D$,an increase in $D$ leads to an increase in the fringe width $\beta$,meaning the interference fringes move farther apart.Additionally,as the screen moves farther away,the intensity of light reaching the screen decreases due to the inverse square law and the spreading of the beam,making the pattern less bright.Therefore,the pattern becomes less bright and the fringes move farther apart.

In Young's double-slit experiment,both slits are illuminated by a laser beam and the interference pattern was observed on a screen. If the viewing screen is moved farther from the slit,what happens to the interference pattern?

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