In Young's double slit experiment,when the wavelength used is $6000 \ \mathring{A}$ and the screen is $40 \ cm$ from the slits,the fringes are $0.012 \ cm$ wide. What is the distance between the slits in $cm$?

In a Young's double slit experiment,$16$ fringes are observed in a certain segment of the screen when light of wavelength $700 \,nm$ is used. If the wavelength of light is changed to $400 \,nm$,the number of fringes observed in the same segment of the screen would be........

In Young's double-slit experiment,if the distance between the slits is twice the wavelength,the number of possible interference maxima is:

$A$ double slit experiment is immersed in water of refractive index $n = 1.33$. The slit separation is $d = 1 \text{ mm}$, and the distance between the slit and the screen is $D = 1.33 \text{ m}$. The slits are illuminated by light of wavelength $\lambda_0 = 6300 \text{ Å}$ in vacuum. The fringe width is:

In Young's double-slit experiment,the width of one slit is twice that of the other. What is the ratio of the maximum to the minimum intensity?

In Young's double slit experiment,white light is used. The separation between the slits is $b$. The screen is at a distance $d$ $(d >> b)$ from the slits. Some wavelengths are missing exactly in front of one slit. These wavelengths are