In Young's double-slit experiment,the positio | vedclass

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(A) Given:Distance between slits and screen,$D = 1\,m$.Wavelength of light,$\lambda = 600\,nm = 600 	imes 10^{-9}\,m$.Position of the $n^{	ext{th}}$

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$60$

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(A) Given:Distance between slits and screen,$D = 1\,m$.Wavelength of light,$\lambda = 600\,nm = 600 	imes 10^{-9}\,m$.Position of the $n^{	ext{th}}$ bright fringe,$y_n = 5\,cm = 5 	imes 10^{-2}\,m$.Order of the fringe,$n = 5$.The formula for the position of the $n^{	ext{th}}$ bright fringe is given by:$y_n = \frac{n \lambda D}{d}$Substituting the given values:$5 	imes 10^{-2} = \frac{5 	imes 600 	imes 10^{-9} 	imes 1}{d}$Rearranging for $d$:$d = \frac{5 	imes 600 	imes 10^{-9}}{5 	imes 10^{-2}}$$d = 600 	imes 10^{-7}\,m = 60 	imes 10^{-6}\,m$Since $1\,\mu m = 10^{-6}\,m$,we have:$d = 60\,\mu m$.

In Young's double-slit experiment,the position of the $5^{\text{th}}$ bright fringe from the central maximum is $5\,cm$. The distance between the slits and the screen is $1\,m$ and the wavelength of the monochromatic light used is $600\,nm$. The separation between the slits is $........\mu m$.

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