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(B) Bond dissociation energy depends on the size of the atoms and the extent of orbital overlap.$1$. For $H-H$ $(436 \ kJ/mol)$,$Cl-Cl$ $(242 \ kJ/mol

Vedclass · Accepted Answer

$Si-Si > C-C > H-H$

Vedclass · Answer

(B) Bond dissociation energy depends on the size of the atoms and the extent of orbital overlap.$1$. For $H-H$ $(436 \ kJ/mol)$,$Cl-Cl$ $(242 \ kJ/mol)$,and $Br-Br$ $(193 \ kJ/mol)$,the order is correct as size increases down the group,decreasing overlap.$2$. For $Si-Si$ $(226 \ kJ/mol)$,$C-C$ $(348 \ kJ/mol)$,and $H-H$ $(436 \ kJ/mol)$,the order $Si-Si > C-C > H-H$ is incorrect because $C-C$ has a higher bond energy than $Si-Si$ due to effective $2p-2p$ overlap compared to $3p-3p$ overlap.$3$. For $C-C$ $(348 \ kJ/mol)$,$N-N$ $(163 \ kJ/mol)$,and $O-O$ $(146 \ kJ/mol)$,the order is correct due to increasing lone pair repulsions.$4$. For $H-Cl$,$H-Br$,and $H-I$,the bond energy decreases as the bond length increases,so the order is correct.Thus,the incorrect order is $Si-Si > C-C > H-H$.

List-$I$	List-$II$
$(P). \ IF_7$	$(a). \ \text{Planar} \ \& \ \text{Polar}$
$(Q). \ SO_2$	$(b). \ \text{Non-planar} \ \& \ \text{Polar}$
$(R). \ SF_4$	$(c). \ \text{Planar} \ \& \ \text{Non-polar}$
$(S). \ CS_2$	$(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$

List-$I$ (Classification of molecules based on octet rule)	List-$II$ (Example)
$A$. Molecules obeying octet rule	$I$. $NO, NO_2$
$B$. Molecules with incomplete octet	$II$. $BCl_3, AlCl_3$
$C$. Molecules with odd electron	$III$. $H_2SO_4, PCl_5$
$D$. Molecules with expanded octet	$IV$. $CCl_4, CO_2$

Which of the following represents the incorrect order of bond dissociation energy?

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Match List-$I$ with List-$II$:

List-$I$ List-$II$

$(P). \ IF_7$ $(a). \ \text{Planar} \ \& \ \text{Polar}$

$(Q). \ SO_2$ $(b). \ \text{Non-planar} \ \& \ \text{Polar}$

$(R). \ SF_4$ $(c). \ \text{Planar} \ \& \ \text{Non-polar}$

$(S). \ CS_2$ $(d). \ \text{Non-planar} \ \& \ \text{Non-polar}$

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