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(D) $1$. For carbocations $(Ph_3C^+ > Ph_2CH^+ > PhCH_2^+)$, stability increases with the number of phenyl groups due to resonance stabilization. This

Vedclass · Accepted Answer

$PhCH_2^- > Ph_2CH^- > Ph_3C^-$

Vedclass · Answer

(D) $1$. For carbocations $(Ph_3C^+ > Ph_2CH^+ > PhCH_2^+)$, stability increases with the number of phenyl groups due to resonance stabilization. This order is correct.$2$. For carbon free radicals $(Ph_3C^• > Ph_2CH^• > PhCH_2^•)$, stability increases with the number of phenyl groups due to resonance. This order is correct.$3$. For carbanions, the negative charge is delocalized over the phenyl rings via resonance. As the number of phenyl groups increases, the extent of delocalization increases, which significantly stabilizes the carbanion. Therefore, the correct order of stability is $PhCH_2^- $4$. Comparing this with the given options, option $D$ $(PhCH_2^- > Ph_2CH^- > Ph_3C^-)$ represents the incorrect order.

Which of the following represents the incorrect order of stability?

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