Iodine is formed when potassium iodide reacts | vedclass

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Question

(B) The correct option is $(B)$.When potassium iodide $(KI)$ reacts with copper sulfate $(CuSO_4)$,it undergoes a redox reaction:$2CuSO_4 + 4KI 	o 2C

Vedclass · Accepted Answer

$CuSO_4$

Vedclass · Answer

(B) The correct option is $(B)$.When potassium iodide $(KI)$ reacts with copper sulfate $(CuSO_4)$,it undergoes a redox reaction:$2CuSO_4 + 4KI 	o 2CuI_2 + 2K_2SO_4$The unstable $CuI_2$ immediately decomposes to form cuprous iodide $(CuI)$ and iodine $(I_2)$:$2CuI_2 	o 2CuI + I_2$Thus,the overall reaction is: $2CuSO_4 + 4KI 	o 2CuI + I_2 + 2K_2SO_4$.

Iodine is formed when potassium iodide reacts with a solution of

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