(D) The catalytic reaction proceeds in two steps:$1$. $2 Fe^{3+} + 2 I^{-} \longrightarrow 2 Fe^{2+} + I_2$$2$. $2 Fe^{2+} + S_2 O_8^{2-} \longrightar

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(D) The catalytic reaction proceeds in two steps:$1$. $2 Fe^{3+} + 2 I^{-} \longrightarrow 2 Fe^{2+} + I_2$$2$. $2 Fe^{2+} + S_2 O_8^{2-} \longrightarrow 2 Fe^{3+} + 2 SO_4^{2-}$In the first step,$Fe^{3+}$ oxidises the iodide ion $(I^-)$ to iodine $(I_2)$ and is reduced to $Fe^{2+}$.In the second step,$Fe^{2+}$ reduces the persulphate ion $(S_2 O_8^{2-})$ to sulphate $(SO_4^{2-})$ and is oxidised back to $Fe^{3+}$.Thus,statements $A$ and $D$ are correct.

Class 12 Chemistry Surface Chemistry Catalyst and Catalysis

Medium

Iron $(III)$ catalyses the reaction between iodide and persulphate ions,in which
$A$. $Fe^{3+}$ oxidises the iodide ion
$B$. $Fe^{3+}$ oxidises the persulphate ion
$C$. $Fe^{2+}$ reduces the iodide ion
$D$. $Fe^{2+}$ reduces the persulphate ion
Choose the most appropriate answer from the options given below:

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$B$ and $C$ only
B
$B$ only
C
$A$ only
D
$A$ and $D$ only

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Match the following.
List-$I$ (Reaction) List-$II$ (Catalyst)
$A$. $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$ $I$. $Ni$
$B$. $2H_{2(g)} + O_{2(g)} \longrightarrow 2H_2O_{(l)}$ $II$. $Pt$
$C$. $CO_{(g)} + 3H_{2(g)} \longrightarrow CH_{4(g)} + H_2O_{(g)}$ $III$. $ZnO-Cr_2O_3$
$D$. $CO_{(g)} + 2H_{2(g)} \longrightarrow CH_3OH_{(g)}$ $IV$. $Fe$

The correct answer is:

List-$I$ (Reaction)	List-$II$ (Catalyst)
$A$. $N_{2(g)} + 3H_{2(g)} \longrightarrow 2NH_{3(g)}$	$I$. $Ni$
$B$. $2H_{2(g)} + O_{2(g)} \longrightarrow 2H_2O_{(l)}$	$II$. $Pt$
$C$. $CO_{(g)} + 3H_{2(g)} \longrightarrow CH_{4(g)} + H_2O_{(g)}$	$III$. $ZnO-Cr_2O_3$
$D$. $CO_{(g)} + 2H_{2(g)} \longrightarrow CH_3OH_{(g)}$	$IV$. $Fe$

EasyAP EAMCET 2019

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Match the following:
List-$I$ (Reaction) List-$II$ (Catalyst)
$A$. Hydrogenation of vegetable oils $I$. $Ni$
$B$. Decomposition of potassium chlorate $II$. $MnO_2$
$C$. Oxidation of $SO_2$ in lead chamber process $III$. $Pt$
$D$. Oxidation of ammonia in Ostwald's process $IV$. $NO_{(g)}$
The correct answer is

List-$I$ (Reaction)	List-$II$ (Catalyst)
$A$. Hydrogenation of vegetable oils	$I$. $Ni$
$B$. Decomposition of potassium chlorate	$II$. $MnO_2$
$C$. Oxidation of $SO_2$ in lead chamber process	$III$. $Pt$
$D$. Oxidation of ammonia in Ostwald's process	$IV$. $NO_{(g)}$

EasyAP EAMCET 2025

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