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(D) The Solar constant is given as $2 \ cal / (cm^2 \cdot min)$.To convert this to $SI$ units $(J / (m^2 \cdot s))$,we perform the following unit conv

Vedclass · Accepted Answer

$1393.33$

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(D) The Solar constant is given as $2 \ cal / (cm^2 \cdot min)$.To convert this to $SI$ units $(J / (m^2 \cdot s))$,we perform the following unit conversions:$1 \ cal = 4.18 \ J$$1 \ min = 60 \ s$$1 \ cm^2 = (10^{-2} \ m)^2 = 10^{-4} \ m^2$Therefore,$1 \ cm^{-2} = 10^4 \ m^{-2}$.Substituting these values:$	ext{Solar constant} = 2 	imes \frac{4.18 \ J}{10^{-4} \ m^2 	imes 60 \ s}$$= 2 	imes 4.18 	imes \frac{10^4}{60} \ J / (m^2 \cdot s)$$= \frac{8.36 	imes 10000}{60} \ J / (m^2 \cdot s)$$= \frac{83600}{60} \ J / (m^2 \cdot s)$$= 1393.33 \ J / (m^2 \cdot s)$.

It is estimated that per minute each $cm^2$ of the Earth receives about $2 \ cal$ $(1 \ cal = 4.18 \ J)$ of heat energy from the Sun. This is called the Solar constant. In $SI$ units,the value is:

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