It is estimated that per minute each cm^2 of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The Solar constant is given as $2 \ cal / (cm^2 \cdot min)$.To convert this to $SI$ units ($W/m^2$ or $J / (m^2 \cdot s)$):$1 \ cal = 4.18 \ J$$1

Vedclass · Accepted Answer

$1393.33$

Vedclass · Answer

(D) The Solar constant is given as $2 \ cal / (cm^2 \cdot min)$.To convert this to $SI$ units ($W/m^2$ or $J / (m^2 \cdot s)$):$1 \ cal = 4.18 \ J$$1 \ min = 60 \ s$$1 \ m^2 = 10^4 \ cm^2$Solar constant $= 2 	imes \frac{4.18 \ J}{10^{-4} \ m^2 	imes 60 \ s}$Solar constant $= 2 	imes 4.18 	imes \frac{10^4}{60} \ J/(m^2 \cdot s)$Solar constant $= \frac{8.36 	imes 10000}{60} \ W/m^2 = \frac{83600}{60} \ W/m^2 = 1393.33 \ W/m^2$.

It is estimated that per minute each $cm^2$ of the Earth receives about $2 \ cal$ $(1 \ cal = 4.18 \ J)$ of heat energy from the Sun. This is called the Solar constant. In $SI$ units,the value is: (in $W/m^2$)

Similar Questions

The unit of energy is:

Write the unit of mass used for atoms and its definition.

Provide a table for the multiples and submultiples of various $SI$ units.

Which of the following physical quantities can be used to express temperature?

$1\,J =$ ............ $\text{calorie}$. (Fill in the blank)

Vedclass Test Series

Exam Paper Generator

Online Exam Module