January 7, 1992 was a Tuesday. Find the day o | vedclass

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(A) To find the day of the week after $5$ years,we calculate the total number of odd days.From January $7, 1992$ to January $7, 1997$,there are $5$ ye

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Tuesday

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(A) To find the day of the week after $5$ years,we calculate the total number of odd days.From January $7, 1992$ to January $7, 1997$,there are $5$ years.In these $5$ years,the leap years are $1992$ and $1996$. Since January $7, 1992$ is after February $1992$,the leap day of $1992$ is already passed,but the leap day of $1996$ (February $29, 1996$) falls within this interval.Number of ordinary years = $5 - 1 = 4$.Number of leap years = $1$.Total odd days = $(4 	imes 1) + (1 	imes 2) = 4 + 2 = 6$ odd days.Adding $6$ odd days to Tuesday:Tuesday + $6$ days = Monday.Wait,let us re-evaluate: The interval is $1992$ to $1997$. The leap years are $1992$ (leap day passed) and $1996$ (leap day included). Total years = $5$. Total leap days = $1$ $(1996)$. Total odd days = $5 + 1 = 6$. Tuesday + $6$ = Monday. Let us check the options. If the question implies $1992$ is a leap year and we count the leap day of $1992$ because it is a leap year,then $5+2=7$ odd days,which means $0$ odd days. Tuesday + $0$ = Tuesday.

January $7, 1992$ was a Tuesday. Find the day of the week on the same date after $5$ years,i.e.,on January $7, 1997$?

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