Kerosene oil rises up the wick in a lantern due to:

If we dip capillary tubes of different radii $r_n$ in water and the water rises to different heights $h_n$ in them, then $(n = 1, 2, 3, ...)$

$A$ $U$-tube with limbs of diameters $5\, mm$ and $2\, mm$ contains water of surface tension $7 \times 10^{-2} \, N/m$. The angle of contact is zero and the density of water is $10^3 \, kg/m^3$. If $g = 10 \, m/s^2$,then the difference in the liquid levels of the two limbs is:

In a capillary,the pressure below the curved surface of water will be:

$A$ glass rod of radius $r_1$ is inserted symmetrically into a vertical capillary tube of radius $r_2$ $(r_1 < r_2)$ such that their lower ends are at the same level. The arrangement is dipped in water. The height to which water will rise into the tube will be ($\rho =$ density of water,$T =$ surface tension of water,$g =$ acceleration due to gravity).

The kerosene oil rises up in the wick of a lamp ...........